Mini Max
0
Posted by admin | Posted in archery | Posted on 07-05-2010
Tags: apple, howto, mac, mini max, mini max aircraft, mini max brooklyn, mini max usa, mini maxx, osx, software
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How to find max and min values?
Find the maximum and minimum values of f(x,y) = x^2 + y^2 subject to the constraint x^4 - y^4 = 1.
I attempted this question and got that the answer should be f(1,0) and f(-1,0) which both equal to 1. Thinking about the 2 functions in 3D, wouldn't it be equal to 1 for every other point as it is a plane? There is is no max and mini values?
f(x,y) = x^2 + y^2
x^4 - y^4 = 1
x^4 = y^4 + 1
x^2 = (y^4 + 1)^(1/2), -y^4 + 1)^(1/2)
f(x,y) = (y^4 + 1)^(1/2) + y^2
f' = (1/2)(y^4 + 1)^(-1/2)(4y^3) + 2y
(1/2)(y^4 + 1)^(-1/2)(4y^3) + 2y = 0
(y^4 + 1)^(-1/2)(y^3) + y = 0
(y^4 + 1)^(-1/2)(y^3) = -y
y^3 = -y(y^4 + 1)^(1/2)
y^6 = y^2(y^4 + 1)
y^6 = y^6 + y^2
y^2 = 0
y = 0
x^4 = y^4 + 1
x^4 = 1
x = 1, -1
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